Problem Statement
given a positive integer n, write a JavaScript program to find the sum of squares of first n natural numbers
Solution
to find the sum of squares of first n natural numbers using JavaScript, we can either use the formula n(n + 1)(2n + 1)/6
, or iterate over a for loop from 1
to n
and accumulate the sum of squares
Program
1. sum of squares of first n natural numbers using formula
n = 10;
sum = n * (n + 1) * (2 * n + 1) / 6;
console.log(`sum of squares of first ${n} natural numbers = ${sum}`);
in the above program, we have used arithmetic multiplication, arithmetic addition, arithmetic division
2. sum of first n natural numbers using for loop
n = 10;
sum = 0;
for ( let i = 1; i <= n; i++) {
sum += i*i;
}
console.log(`sum of squares of first ${n} natural numbers = ${sum}`);