Find sum of squares of first n natural numbers in JavaScript
In this tutorial, you are given a positive integer n, and you to write a JavaScript program to find the sum of squares of first n natural numbers.
Solution
To find the sum of squares of first n natural numbers using JavaScript, we can either use the formula n(n + 1)(2n + 1)/6
, or iterate over a for loop from 1
to n
and accumulate the sum of squares.
Programs
1. Sum of squares of first n natural numbers using formula.
n = 10;
sum = n * (n + 1) * (2 * n + 1) / 6;
console.log(`sum of squares of first ${n} natural numbers = ${sum}`);
In the above program, we have used arithmetic multiplication, arithmetic addition, arithmetic division.
2. Sum of first n natural numbers using for loop.
n = 10;
sum = 0;
for ( let i = 1; i <= n; i++) {
sum += i*i;
}
console.log(`sum of squares of first ${n} natural numbers = ${sum}`);